TEST 10
1.
\(m\left(\widehat{BAD}\right)=m\left(\widehat{DAC}\right)\)
\(m\left(\widehat{ABD}\right)=m\left(\widehat{DBC}\right)\)
\(m\left(\widehat{ADE}\right)=40^\circ\)
\(m\left(\widehat{EDB}\right)=60^\circ\)
\(\Rightarrow m\left(\widehat{ACE}\right)=\alpha=?\)
A) \(5\)B) \(10\)C) \(15\)D) \(20\)E) \(25\)
2.
\(m\left(\widehat{EBD}\right)=m\left(\widehat{DBC}\right)\)
\(m\left(\widehat{BCD}\right)=m\left(\widehat{DCK}\right)\)
\(m\left(\widehat{BDA}\right)=15^\circ\)
\(m\left(\widehat{ADC}\right)=30^\circ\)
\(\Rightarrow m\left(\widehat{DAK}\right)=\alpha=?\)
A) \(35\)B) \(40\)C) \(45\)D) \(50\)E) \(55\)
3.
\(m\left(\widehat{BAC}\right)=80^\circ\)
\(m\left(\widehat{CAD}\right)=50^\circ\)
\(m\left(\widehat{BCA}\right)=30^\circ\)
\(m\left(\widehat{ACD}\right)=75^\circ\)
\(\Rightarrow m\left(\widehat{ADB}\right)=\alpha=?\)
A) \(10\)B) \(15\)C) \(30\)D) \(40\)E) \(50\)
4.
\(m\left(\widehat{ACE}\right)=m\left(\widehat{ECB}\right)\)
\(m\left(\widehat{ADE}\right)=m\left(\widehat{EDB}\right)\)
\(m\left(\widehat{BAD}\right)=65^\circ\)
\(\Rightarrow m\left(\widehat{DEC}\right)=\alpha=?\)
A) \(130\)B) \(65\)C) \(50\)D) \(25\)E) \(20\)
5.
\(m\left(\widehat{BAD}\right)=m\left(\widehat{DAC}\right)\)
\(m\left(\widehat{BCA}\right)=78^\circ\)
\(m\left(\widehat{BCD}\right)=51^\circ\)
\(\Rightarrow m\left(\widehat{BDA}\right)=\alpha=?\)
A) \(28\)B) \(39\)C) \(56\)D) \(78\)E) \(90\)
6.
\(m\left(\widehat{BAC}\right)=m\left(\widehat{CAD}\right)\)
\(m\left(\widehat{ABD}\right)=30^\circ\)
\(m\left(\widehat{DBC}\right)=75^\circ\)
\(\Rightarrow m\left(\widehat{ACD}\right)=\alpha=?\)
A) \(150\)B) \(75\)C) \(60\)D) \(30\)E) \(15\)
7.
\(m\left(\widehat{ABD}\right)=m\left(\widehat{DBC}\right)\)
\(m\left(\widehat{ACD}\right)=m\left(\widehat{DCB}\right)\)
\(m\left(\widehat{CBE}\right)=m\left(\widehat{EBG}\right)\)
\(m\left(\widehat{BCE}\right)=m\left(\widehat{ECF}\right)\)
\(m\left(\widehat{BDC}\right)=\alpha+40^\circ\)
\(m\left(\widehat{BEC}\right)=\alpha-20^\circ\)
\(\Rightarrow m\left(\widehat{GAF}\right)=?\)
A) \(30\)B) \(45\)C) \(60\)D) \(80\)E) \(90\)
8.
\(m\left(\widehat{BDC}\right)=115^\circ\)
\(m\left(\widehat{ABE}\right)=m\left(\widehat{EBF}\right)\)
\(m\left(\widehat{BCD}\right)=m\left(\widehat{DCA}\right)\)
\(m\left(\widehat{ACE}\right)=m\left(\widehat{ECF}\right)\)
\(\Rightarrow m\left(\widehat{BEC}\right)=\alpha=?\)
A) \(15\)B) \(25\)C) \(30\)D) \(35\)E) \(40\)