TEST 15
1.
\(d_1\parallel d_2\)
\(m\left(\widehat{ABC}\right)=120^\circ\)
\(m\left(\widehat{BCD}\right)=40^\circ\)
\(\Rightarrow m\left(\widehat{CDE}\right)=\alpha=?\)
A) \(70\)B) \(80\)C) \(90\)D) \(100\)E) \(110\)
2.
\(d_1\parallel d_2\)
\(m\left(\widehat{ABC}\right)=70^\circ\)
\(m\left(\widehat{MHO}\right)=70^\circ\)
\(m\left(\widehat{CDF}\right)=m\left(\widehat{FDB}\right)\)
\(\Rightarrow m\left(\widehat{FEK}\right)=\alpha=?\)
A) \(10\)B) \(20\)C) \(30\)D) \(50\)E) \(70\)
3.
\(d_1\parallel d_2\)
\(m\left(\widehat{ABC}\right)=70^\circ\)
\(m\left(\widehat{CDF}\right)=m\left(\widehat{FDE}\right)\)
\(m\left(\widehat{BCF}\right)=m\left(\widehat{FCD}\right)\)
\(\Rightarrow m\left(\widehat{CFD}\right)=\alpha=?\)
A) \(45\)B) \(50\)C) \(55\)D) \(60\)E) \(65\)
4.
\(d_1\parallel d_2\)
\([DE\parallel[KC\)
\(m\left(\widehat{ABC}\right)=m\left(\widehat{CBD}\right)\)
\(m\left(\widehat{KDE}\right)=45^\circ\)
\(m\left(\widehat{DEF}\right)=80^\circ\)
\(\Rightarrow m\left(\widehat{BDK}\right)=\alpha=?\)
A) \(35\)B) \(40\)C) \(45\)D) \(50\)E) \(55\)
5.
\(d_1\parallel d_2\)
\([DC]\parallel[EF]\)
\(m\left(\widehat{ABC}\right)=140^\circ\)
\(m\left(\widehat{EFG}\right)=110^\circ\)
\(m\left(\widehat{CDE}\right)=150^\circ\)
\(\Rightarrow m\left(\widehat{BCD}\right)=\alpha=?\)
A) \(20\)B) \(30\)C) \(40\)D) \(50\)E) \(60\)
6.
\(d_1\parallel d_2\)
\([AB]\parallel[DF\)
\(m\left(\widehat{ACB}\right)=75^\circ\)
\(m\left(\widehat{KEF}\right)=35^\circ\)
\(m\left(\widehat{DAB}\right)=x\)
\(\Rightarrow m\left(\widehat{ABC}\right)=y=?\)
A) \(25\)B) \(30\)C) \(35\)D) \(40\)E) \(45\)
7.
\(d_1\parallel d_2\)
\(m\left(\widehat{AEG}\right)=100^\circ\)
\(m\left(\widehat{GFC}\right)=50^\circ\)
\(m\left(\widehat{FCB}\right)=m\left(\widehat{BCD}\right)\)
\(\Rightarrow m\left(\widehat{ABC}\right)=\alpha=?\)
A) \(50\)B) \(70\)C) \(100\)D) \(115\)E) \(120\)
8.
\(d_1\parallel d_2\)
\(d_3\parallel d_4\parallel d_5\)
\(m\left(\widehat{ABC}\right)=40^\circ\)
\(m\left(\widehat{BCD}\right)=126^\circ\)
\(m\left(\widehat{DEF}\right)=m\left(\widehat{FEG}\right)\)
\(\Rightarrow m\left(\widehat{KFE}\right)=\alpha=?\)
A) \(94\)B) \(104\)C) \(117\)D) \(127\)E) \(137\)